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发表于 2020-4-22 16:49:01 | 查看: 4954| 回复: 0

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♦ rsa

>>> c=4153372421328787064168548641845708183921443446990158572506114559735441950501706984118235944441928889749083563790293558028143373121367441549974248211570336802004821051820943229232421937298269855190652251294220483768084460779714162849925877879859830009443131489814222929347727735616113359695228615432020363240247474622132986939108457393618346100033147945959684443762976681454755482192433993286205527003029269574787026484389622816932835184754540312561890719407986296481186847292967270288752616
>>> gmpy2.iroot(c,3)
(mpz(16074357572745018593418837326290993512421736655307780242162599660198598253230550168811761868953242350136362894008095983571749530656901163555918436741973772511575306L), True)

>>> x=16074357572745018593418837326290993512421736655307780242162599660198598253230550168811761868953242350136362894008095983571749530656901163555918436741973772511575306
>>> x=libnum.n2s(16074357572745018593418837326290993512421736655307780242162599660198598253230550168811761868953242350136362894008095983571749530656901163555918436741973772511575306)
>>> x1=x[::-1].encode('rot13')
>>> x1
'This is the password you need for the ZIP file: flag{rsaM0reD33peR}\n'


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